sklearn.metrics
.normalized_mutual_info_score¶
- sklearn.metrics.normalized_mutual_info_score(labels_true, labels_pred, *, average_method='arithmetic')[source]¶
Normalized Mutual Information between two clusterings.
Normalized Mutual Information (NMI) is a normalization of the Mutual Information (MI) score to scale the results between 0 (no mutual information) and 1 (perfect correlation). In this function, mutual information is normalized by some generalized mean of
H(labels_true)
andH(labels_pred))
, defined by theaverage_method
.This measure is not adjusted for chance. Therefore
adjusted_mutual_info_score
might be preferred.This metric is independent of the absolute values of the labels: a permutation of the class or cluster label values won’t change the score value in any way.
This metric is furthermore symmetric: switching
label_true
withlabel_pred
will return the same score value. This can be useful to measure the agreement of two independent label assignments strategies on the same dataset when the real ground truth is not known.Read more in the User Guide.
- Parameters
- labels_trueint array, shape = [n_samples]
A clustering of the data into disjoint subsets.
- labels_predint array-like of shape (n_samples,)
A clustering of the data into disjoint subsets.
- average_methodstr, default=’arithmetic’
How to compute the normalizer in the denominator. Possible options are ‘min’, ‘geometric’, ‘arithmetic’, and ‘max’.
New in version 0.20.
Changed in version 0.22: The default value of
average_method
changed from ‘geometric’ to ‘arithmetic’.
- Returns
- nmifloat
score between 0.0 and 1.0. 1.0 stands for perfectly complete labeling
See also
v_measure_score
V-Measure (NMI with arithmetic mean option).
adjusted_rand_score
Adjusted Rand Index.
adjusted_mutual_info_score
Adjusted Mutual Information (adjusted against chance).
Examples
Perfect labelings are both homogeneous and complete, hence have score 1.0:
>>> from sklearn.metrics.cluster import normalized_mutual_info_score >>> normalized_mutual_info_score([0, 0, 1, 1], [0, 0, 1, 1]) ... 1.0 >>> normalized_mutual_info_score([0, 0, 1, 1], [1, 1, 0, 0]) ... 1.0
If classes members are completely split across different clusters, the assignment is totally in-complete, hence the NMI is null:
>>> normalized_mutual_info_score([0, 0, 0, 0], [0, 1, 2, 3]) ... 0.0